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Increasing epsilon decreases noise #15

@echo66

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@echo66

Greetings!

I'm trying to understand your paper and implementation. I've noticed that the more you increase epsilon, the less noise will be generated. In order to understand if that is the expected behavior, I looked into your paper and PrivBayes paper (and, also, a Java implementation) and everyone seems to say that the scale of the noise is given by:

4 * (n_cols - k) / (n_rows * epsilon)

But the definition of differential privacy implies that if epsilon gets closer to 0, there won't be any difference for the query output between the original and synthetic datasets. Am I getting something wrong?

Thanks in advance!

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