(tanx)'=sec²x=1+tan²x #2
Description
i think this is right!
def backward(self, X, top_diff):
output = self.forward(X)
return (1.0 + np.square(output)) * top_diff
beacuse (tanx)'=sec²x=1+tan²x
{{ message }}
i think this is right!
def backward(self, X, top_diff):
output = self.forward(X)
return (1.0 + np.square(output)) * top_diff
beacuse (tanx)'=sec²x=1+tan²x