717. 1-bit and 2-bit Characters

[mah-shamim]

Topics: Array

We have two special characters:

• The first character can be represented by one bit 0.
• The second character can be represented by two bits (10 or 11).

Given a binary array bits that ends with 0, return true if the last character must be a one-bit character.

Example 1:

• Input: bits = [1,0,0]
• Output: true
• Explanation: The only way to decode it is two-bit character and one-bit character.
  So the last character is one-bit character.

Example 2:

• Input: bits = [1,1,1,0]
• Output: false
• Explanation: The only way to decode it is two-bit character and two-bit character.
  So the last character is not one-bit character.

Constraints:

• 1 <= bits.length <= 1000
• bits[i] is either 0 or 1.

Hint:

1. Keep track of where the next character starts. At the end, you want to know if you started on the last bit.

[mah-shamim]

We need to determine if the last character in a binary array (ending with 0) must be a one-bit character. The two valid characters are:

• One-bit: 0
• Two-bit: 10 or 11

The key is to traverse the array and decode the characters. If we end exactly at the last bit, it must be a one-bit character. Otherwise, if we skip over the last bit (meaning it was part of a two-bit character), it's not a one-bit character.

Approach:

We'll traverse the array from left to right. When we encounter a 1, it must be the start of a two-bit character, so we skip the next bit. When we encounter a 0, it's a one-bit character, so we move to the next bit. We continue until we reach or pass the last bit. If we land exactly on the last bit, it must be a one-bit character.

Let's implement this solution in PHP: 717. 1-bit and 2-bit Characters

<?php
/**
 * @param Integer[] $bits
 * @return Boolean
 */
function isOneBitCharacter($bits) {
    $i = 0;
    $n = count($bits);
    while ($i < $n - 1) {
        if ($bits[$i] == 1) {
            $i += 2;
        } else {
            $i += 1;
        }
    }
    return $i == $n - 1;
}

// Test cases
echo isOneBitCharacter([1,0,0]) . "\n";     // Output: true
echo isOneBitCharacter([1,1,1,0]) . "\n";   // Output: false
?>

Explanation:

1. Initialization: Start at the first bit ($i = 0).
2. Traversal: Loop until we reach the second last bit ($i < $n - 1).
   • If the current bit is 1, it's a two-bit character, so skip the next bit ($i += 2).
   • If the current bit is 0, it's a one-bit character, so move to the next bit ($i += 1).
3. Check Position: After the loop, if $i is exactly at the last bit ($n - 1), the last character is a one-bit character. Otherwise, it was part of a two-bit character.

This approach efficiently decodes the array in a single pass, ensuring optimal performance with O(n) time complexity and O(1) space complexity.

[basharul-siddike]

Thanks for solving the problem of "1-bit and 2-bit Characters"

[mah-shamim]

Thanks