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Hello @mdeff ,
MNIST data are defined on 2D grid. Hence, we build graph on MNIST by supposing that each pixel is a node and the max number edges per node is 8. Hence, we have a regular and fixed graphs.
The Fourier basis is obtained by computing the Laplacian of the graph. Since the graphs are regulars, you pick at random a graph encoding an exemple of MNIST and compute its laplacian. This latter is used as the Fourier basis of MNIST.
- Why we don't compute the laplacian of each training exemple ?
- How do you explain that taking any Laplacian of MNIST example represents the Fourier Basis of the whole data ? Is there any effect on the stability of the Fourier Basis ? Does it apply also to irrigular graphs ?
Thank you for your answer.
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