Generated query to use rdf:type in match #57
Description
When I generate a SPARQL query from a GraphQL query, I always see the statement in the WHERE clause is something like:
?df_3_0 <http://example.org/hero> ?hero.
which won't match anything in our knowledge base and thus cause the query to return with no results.
What I was expected was a statement more like:
?hero <http://www.w3.org/1999/02/22-rdf-syntax-ns#type> <http://example.org/hero>
which would then be followed by the remainder of the statements used to obtain the predicate values of interest.
Is there a way to get the code to generate that? Perhaps I've missed something.