AsyncSemaphore and AsyncPriorityQueue. #147
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arnetheduck
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Jan 13, 2021
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| if i > 0: | ||
| waiters.delete(0, i - 1) | ||
| # Workaround for callSoon() not worked correctly before |
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callSoon calls getThreadDispatcher, why should this be needed here?
arnetheduck
reviewed
Jan 13, 2021
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| proc release*(asem: AsyncSemaphore) = | ||
| ## Release a semaphore, incrementing internal counter by one. | ||
| if asem.counter >= asem.maxcounter: |
arnetheduck
reviewed
Jan 13, 2021
| ## If the internal counter is larger than zero on entry, decrement it by one | ||
| ## and return immediately. If its zero on entry, block and wait until some | ||
| ## other task has called ``release()`` to make it larger than 0. | ||
| while asem.counter <= 0: |
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the loop should not be needed here - there will be exactly one queue item per count below zero so they should line up perfectly
vladopajic
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