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42 changes: 42 additions & 0 deletions src/codingquestions/leetcode/LargestPerimeterTriangle.java
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/*
976. Largest Perimeter Triangle
Solved
Easy
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Given an integer array nums, return the largest perimeter of a triangle with a non-zero area, formed from three of these lengths. If it is impossible to form any triangle of a non-zero area, return 0.



Example 1:

Input: nums = [2,1,2]
Output: 5
Explanation: You can form a triangle with three side lengths: 1, 2, and 2.
Example 2:

Input: nums = [1,2,1,10]
Output: 0
Explanation:
You cannot use the side lengths 1, 1, and 2 to form a triangle.
You cannot use the side lengths 1, 1, and 10 to form a triangle.
You cannot use the side lengths 1, 2, and 10 to form a triangle.
As we cannot use any three side lengths to form a triangle of non-zero area, we return 0.


Constraints:

3 <= nums.length <= 104
1 <= nums[i] <= 106
*/
class Solution {
public int largestPerimeter(int[] nums) {
Arrays.sort(nums);
for(int i = nums.length - 3; i >= 0; i--){
if(nums[i] + nums[i + 1] > nums[i + 2])
return nums[i] + nums[i + 1] + nums[i + 2];
}
return 0;
}
}