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fix: use deterministic comparison ordering #161
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@@ -859,18 +859,17 @@ def _item_replaced(self, path, key, item): | |||||||||||||||
}, pointer_cls=self.pointer_cls)) | ||||||||||||||||
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def _compare_dicts(self, path, src, dst): | ||||||||||||||||
src_keys = set(src.keys()) | ||||||||||||||||
dst_keys = set(dst.keys()) | ||||||||||||||||
added_keys = dst_keys - src_keys | ||||||||||||||||
removed_keys = src_keys - dst_keys | ||||||||||||||||
added_keys = [key for key in dst.keys() if key not in src.keys()] | ||||||||||||||||
removed_keys = [key for key in src.keys() if key not in dst.keys()] | ||||||||||||||||
intersection = [key for key in src.keys() if key in dst.keys()] | ||||||||||||||||
Comment on lines
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Similar to the line above, this will have O(n²) complexity. Use
Suggested change
Copilot uses AI. Check for mistakes. Positive FeedbackNegative Feedback There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. This also has O(n²) complexity. Use
Suggested change
Copilot uses AI. Check for mistakes. Positive FeedbackNegative Feedback |
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for key in removed_keys: | ||||||||||||||||
self._item_removed(path, str(key), src[key]) | ||||||||||||||||
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for key in added_keys: | ||||||||||||||||
self._item_added(path, str(key), dst[key]) | ||||||||||||||||
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for key in src_keys & dst_keys: | ||||||||||||||||
for key in intersection: | ||||||||||||||||
self._compare_values(path, key, src[key], dst[key]) | ||||||||||||||||
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def _compare_lists(self, path, src, dst): | ||||||||||||||||
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The list comprehension with
if key not in src.keys()
will result in O(n²) time complexity for large dictionaries sincein
operation on dict.keys() is O(n). Consider usingadded_keys = [key for key in dst if key not in src]
instead, which maintains O(n) complexity.Copilot uses AI. Check for mistakes.